56x^2-15x^2-56=0

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Solution for 56x^2-15x^2-56=0 equation:



56x^2-15x^2-56=0
We add all the numbers together, and all the variables
41x^2-56=0
a = 41; b = 0; c = -56;
Δ = b2-4ac
Δ = 02-4·41·(-56)
Δ = 9184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{9184}=\sqrt{16*574}=\sqrt{16}*\sqrt{574}=4\sqrt{574}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{574}}{2*41}=\frac{0-4\sqrt{574}}{82} =-\frac{4\sqrt{574}}{82} =-\frac{2\sqrt{574}}{41} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{574}}{2*41}=\frac{0+4\sqrt{574}}{82} =\frac{4\sqrt{574}}{82} =\frac{2\sqrt{574}}{41} $

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